Quotients by submodules #
- If
pis a submodule ofM,M ⧸ pis the quotient ofMwith respect top: that is, elements ofMare identified if their difference is inp. This is itself a module.
Main definitions #
Submodule.Quotient.restrictScalarsEquiv: The quotient ofPas anS-submodule is the same as the quotient ofPas anR-submodule,Submodule.liftQ: lift a mapM → M₂to a mapM ⧸ p → M₂if the kernel is contained inpSubmodule.mapQ: lift a mapM → M₂to a mapM ⧸ p → M₂ ⧸ qif the image ofpis contained inq
The quotient of P as an S-submodule is the same as the quotient of P as an R-submodule,
where P : Submodule R M.
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The map from the quotient of M by a submodule p to M₂ induced by a linear map f : M → M₂
vanishing on p, as a linear map.
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Special case of submodule.liftQ when p is the span of x. In this case, the condition on
f simply becomes vanishing at x.
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The map from the quotient of M by submodule p to the quotient of M₂ by submodule q along
f : M → M₂ is linear.
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Given submodules p ⊆ M, p₂ ⊆ M₂, p₃ ⊆ M₃ and maps f : M → M₂, g : M₂ → M₃ inducing
mapQ f : M ⧸ p → M₂ ⧸ p₂ and mapQ g : M₂ ⧸ p₂ → M₃ ⧸ p₃ then
mapQ (g ∘ f) = (mapQ g) ∘ (mapQ f).
The linear map from the quotient by a smaller submodule to the quotient by a larger submodule.
This is the Submodule.Quotient version of Quot.Factor
When the two submodules are of the form I ^ m • ⊤ and I ^ n • ⊤ and n ≤ m,
please refer to the dedicated version Submodule.factorPow.
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The correspondence theorem for modules: there is an order isomorphism between submodules of the
quotient of M by p, and submodules of M larger than p.
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If P is a submodule of M and Q a submodule of N,
and f : M ≃ₗ N maps P to Q, then M ⧸ P is equivalent to N ⧸ Q.
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An epimorphism is surjective.
Given modules M, M₂ over a commutative ring, together with submodules p ⊆ M, q ⊆ M₂,
the natural map $\{f ∈ Hom(M, M₂) | f(p) ⊆ q \} \to Hom(M/p, M₂/q)$ is linear.